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39q^2-44q=0
a = 39; b = -44; c = 0;
Δ = b2-4ac
Δ = -442-4·39·0
Δ = 1936
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$q_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$q_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1936}=44$$q_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-44)-44}{2*39}=\frac{0}{78} =0 $$q_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-44)+44}{2*39}=\frac{88}{78} =1+5/39 $
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